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The demand for grass seed (in thousands of pounds) at a price of p dollars is D(p) = -3p3 - 2p2+ 1500 Use the differential
The demand for grass seed (in thousands of pounds) at a price of p dollars is D(p) = -3p3 - 2p2+ 1500 Use the differential to approximate the change in demand for a change in p from $2 to $2.10. Find each of the following. 3x3-2x2+x-5 4x2 dx (Hint: Simplify the integrand first) ex-ex ( exte - x ) 1 / 2 dx Use the midpoint rule with n = 6 subintervals to approximate the area of the region bounded by the graph of the function f and the x axis over the interval given. f (x) = xex; x = 0tox = 6
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