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The demand function for particular watch is given by p = 620 - 5x where p is the price per watch and x is

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The demand function for particular watch is given by p = 620 - 5x where p is the price per watch and x is the number of watches sold. (a) Find the revenue function, R(x): = (b) Determine the number of watches that must be sold to maximize revenue. watches x + (c) What is the maximum revenue? $ (d) What is the price per unit when the revenue is maximized? $

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