The diagram shows two plates held together by a 10 mm bolt (which can be assumed to have an effective diameter of 9.5 mm. The bolt is tensioned to 20 KN and subjected to a shearing force by the plates of 10 KN. The ultimate tensile strength of the bolt material is 500 MN/m and the ultimate shear strength is 300 MN/m. i) ii) iii) 20 kN -M10 Nut and bolt 10 kN Calculate the factor of safety in tension Calculate the factor of safety in shear From your results to i) and ii) state the factor of safety in operation, ie the effective overall factor of safety. The diagram shows two plates held together by a 10 mm bolt (which can be assumed to have an effective diameter of 9.5 mm. The bolt is tensioned to 20 KN and subjected to a shearing force by the plates of 10 KN. The ultimate tensile strength of the bolt material is 500 MN/m and the ultimate shear strength is 300 MN/m. i) ii) iii) 20 kN -M10 Nut and bolt 10 kN Calculate the factor of safety in tension Calculate the factor of safety in shear From your results to i) and ii) state the factor of safety in operation, ie the effective overall factor of safety.