The differential equation for the curve y=g(x) is given by dy/dx = 2^x(y-1). It is known that
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Question:
The differential equation for the curve y=g(x) is given by dy/dx = 2^x(y-1). It is known that g(1)=0 and g is twice differentiable.
lim x-->1 sin(g(x)) / x^2 - x
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