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the dimensions are a = 6 mm and b = 8 mm . Given that: dA for Ix is = 6*(sqrt(y/8)-y/8)dy dA for Iy is

the dimensions are a = 6 mm and  b = 8 mm

     Given that: dA for Ix is = 6*(sqrt(y/8)-y/8)dy

    dA for Iy is = 8/6*(1-(x/6))xdx

    After computing further, we get: Ix=110m^(4),  Iy=86.4m^(4)

Find the polar moment of inertia for the entire area shown in figure above.


y b. a y b. a

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