The director tells that the test gives a false positive 2% of the times. Again, 0.4% of the device have the defect, and the test idenfities it in 97% of the faulty devices.

P(D) = 0.004

P(Dc) = 0.996

P(T|D) = 0.97

P(T|Dc) = ?

After looking for the chance that a device has this defect after testing positive for it or {(D|T). Using the LTP version of Bayes rule, you find that only .........(?) % of the devices test positive are in fact defective.....