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The dissociation of molecular lodine into iodine atoms is represented as 12(g)21(g) At 1000.0K, the cquilibrium constant Ke for the reaction is 3.80105. Suppose you

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The dissociation of molecular lodine into iodine atoms is represented as 12(g)21(g) At 1000.0K, the cquilibrium constant Ke for the reaction is 3.80105. Suppose you start with 0.0457 mol of I2 in a 2.27L flask at 1000.0K. What are the concentrations of the gases at equilibrium? Part 1 of 2 What is the equilibrium concentration of L2 ? Round your answer to 3 significant digits. Part 2 of 2 What is the equitibrium concentration of 17 Round youf answer to 3 significant digits

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