The distance from the star S to the planet X is approximately 149?700?000 kilometers? (km). The distance from S to the planet Y is approximately 57?830?000 km. The elongation angle is the angle formed between the line of sight from X to S and the line of sight from X to Y. See the figure on the right. Suppose that the elongation angle is . Use this information to find the possible distances between X and Y.The larger and smaller distance from X to Y is enter your response here km.

Math 2+2C Fall 2021 Homework: 7.2 The Law of Sines (16) Question 16, 7.2.57 HW Score: 93.75%, 15 of 16 points Part 1 of 2 x Points: 0 of 1 The distance from the star S to the planet X is approximately 149,700,000 kilometers (km). The distance from S to the planet Y is approximately 57,830,000 km. The elongation angle a is the angle formed between the line of sight from X to S and the line of sight from X to Y. See the figure on the right. Suppose that the elongation angle is 14. Use this information to find the possible distances between X and Y. X The larger distance from X to Y is km. (Do not round until the final answer. Then round to one decimal place as needed.)