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The drag force F for a solid spherical particle moving in fluid is F=f*(nr)*/ pv. Following plot shows f as a function of Re.

The drag force F for a solid spherical particle moving in fluid is F=f*(nr)*/ pv. Following plot shows f as a

The drag force F for a solid spherical particle moving in fluid is F=f*(nr)*/ pv. Following plot shows f as a function of Re. (a) When Re is very small, the terminal velocity is proportional to ra, while when Re is in the range between 2000 and 100000 (where f-0.44), terminal velocity is proportional to rb. Start from force balance and find a and b. (b) For a spherical particle (density pp-1100 kg/m^3, diameter Dp=0.02*10- m) falling in water (density p=1000 kg/m^3, viscosity =10 kg/m.s). Find the terminal velocity of this particle. 104 Friction factor f 103 100 10 1.0 0.1 10-32 Stokes' law asymptote f = 5 10-22 5 10-12 5 24 Re 1 2 =(/24+0.5407) Re up to about Re = 6103 5 10 5 5 5 103 2 102 2 Reynolds number Re = Dv. p/u 2 104 2 5 105 2 5 106 FD= 0144 721 5 Pr Fs = exfar g Ig=mg

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