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The drawing on page 2 shows the situation: (We are using a right-handed coordinate system, so +x is to the right, +y is upward, and

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The drawing on page 2 shows the situation: (We are using a right-handed coordinate system, so +x is to the right, +y is upward, and +z is out of the page.) A long wire carrying a current of 5 amperes into the page (negative z direction) pierces the x-y plane at (0,0). The particle we're interested in is in the x-y plane, at (-.02, .05, 0) meters, and this point is called point P. Assume that the only force this particle feels is due to its proximity to the current-carrying wire. At the instant the particle is at point P it has the following velocity and acceleration vectors: = (3.27 -8.17 + 0.3k) . 10'm/s d= (-8.863 . 1057+2.216 - 105/ +6.928 - 107k) m/s? End of given information. Find that isotope! Drawing on next page .. Scanned with CamScanner P 2) (-.02m, .05m, Om) " +z(out) +x I'm ( 5 amps )

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