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The electric field of the material between two coaxial cables of radius .25 m and .51 m is given as E = 2.58 V.m/r^3. If

The electric field of the material between two coaxial cables of radius .25 m and .51 m is given as E = 2.58 V.m/r^3. If the conductivity of the material is 5 10^10 S/m, what is the current density in the material

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