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The energy of the first excited quantum state of a particle in the 2-Dim. potential: V(x, y) = 1/2mw^2(x^2+4y^2) is:
The energy of the first excited quantum state of a particle in the 2-Dim. potential: V(x, y) = 1/2mw^2(x^2+4y^2) is:
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Chemical Principles
Authors: Steven S. Zumdahl, Donald J. DeCoste
7th edition
9781133109235, 1111580650, 978-1111580650
