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The equilibrium constant for the reaction H2(g) + Bry(g) = 2 HBr (9) is 2.180 x 10 at 730.0 C. Starting with 2.20 moles of

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The equilibrium constant for the reaction H2(g) + Bry(g) = 2 HBr (9) is 2.180 x 10 at 730.0 C. Starting with 2.20 moles of HBr in a 14.9 L reaction vessel, calculate the concentrations of H., Bry, and HBr at equilibrium Part: 0/2 Part 1 of 2 Be sure each of your answer entries has the correct number of significant digits. [] -OM [Bry] X

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