The equilibrium constant, K, for the following reaction is 1.29x102 at 600 K. COCI(g)=CO(g) + Cl(g) An equilibrium mixture of the three gases in a 1.00 L flask at 600 K contains 0.173 M COCI, 4.72x10-2 M CO and 4.72x10 M Cl- What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.54x10-2 mol of CO(g) is added to the flask? [COCI] = [CO] [Cl] 1111