The figure below shows a dipole. If the positive particle has a charge of 32.1 mC and the particles are 2.50 mm apart, what is the electric field at point A located 2.00 mm above the dipole's midpoint? (Express your answer in vector form.) E = Oi N/C X A + - X d/2 d/2The charge density on a disk of radius R = 12.2 cm is given by o = ar, with a = 1.32 uC/m3 and r measured radially outward from the origin (see figure below). What is the electric potential at point A, a distance of 44.0 cm above the disk? Hint: You will need to integrate the nonuniform charge density to find the electric potential. You will find a table of integrals helpful for performing the integration. e x Your response differs from the correct answer by more than 10%. Double check your calculations. V