The first stage in the manufacture of sulphuric acid from iron pyrites $($FeS$2)$ involves combustion in air:

$2$ FeS$2($s$)+5$ O$2($g$)-->2$ FeO$($s$)+4$SO$2($g$)$

The solid feed contains $90\%$ w$/$w of FeS$2,$ the remainder being inert material. A $50\%$ excess of air is supplied beyond that stoichiometrically required for the above reaction. This air supply can be taken as $21\%$ v$/$v of O$2$ and $79\%$ v$/$v of N$2.$ All of the FeS$2$ reacts so that the solid waste stream contains only FeO and the inert solid from the feed.

$($i$)$ Draw, and fully label, a box diagram for this process.

For each tonne of solid feed supplied, calculate:

$($ii$)$ the volume of air to be supplied $($at $15$ oC and $1$ bar pressure$)$;

$($iii$)$ the molar composition of the output gas stream;

$($iv$)$ the volume of output gas to be handled $($at $600$ oC and $1$ bar pressure$)$;

$($v$)$ the mass of waste solid produced.