The following 5 questions are based on this information.

In a poll of 500 Graduat students, .75% (p=0.75)said that they used only Internet for the project and assignment purposes..

The goal is to construct a 99% confidence interval for the percentage (p) of Graduatel students who use the Internet for project and assignment purposes.

1)The standard error (SE) ofp is'

2)The critical value (CV) needed for 99% confidence interval estimation is

3)The 99% confidence interval estimate of p is

4)Suppose around the period the above poll was conducted,The DEan of a university made a personal statement saying that .85% of Graduate students used only the Internet for assignment purposes

In light of the sample evidence and at the 1% level of significance, REJECT?

5) A Dean of the universityl wishes to collect new random sample with the aim of building a new confidence interval at the 99% confidence level for p.Using the current sample proportion (from the 500 graduate students poll ) as a basis, what sample size (n) would the journalist require to achieve a 10% margin of error?

please show step by step, equations . dumbproof it to the best of your ability

please dont type like this P[ |X(bar)-| <25] =P[ |(X(bar)-)/(/sqrt(n))| <25>