The following data are from a completelv randomized design. Treatment Tftl'l'll'lt Treatment A B C 32 44 33 30 43 36 30 44 35 26 46 36 32 48 40 Sample mean 30 45 36 Sample variance 6.00 4.00 6.50 a. At the a = 0.05 level of signicance, can we reject the null hvpothesis that the means of the three treatments are equal? Compute the values below {to 1 decimal, if necessary]. Sum of Squares, Treatment 5?0 9 Sum of Squares, Error 66 9 Mean Squares, Treatment 285 @ Mean Squares, Error 5.5 (9 Calculate the value of the test statistic [to 2 decimals}. 51.82 Q T..,-..I..i_@ IIl'll'hat is your conclusion".rI Cor-Elude that not all tI-eatrnent means are equal V 9 I}. Calculate the value of Fisher's LSD {to 2 decimals]. 8 Use Fisher's LSD procedure to test whether there is a signicant difference between the means for treatments A and B, treatments A and C, and treatments B and C. Use a: = 0.05. Difference Absolute 1value Conclusion mEB *3 @ EM. 9 @ EM... 0 c. Use Fisher's LSD procedure to develop a 95% condence interval estimate of the difference between the means of treatments A and B {to 2 decimals}. Enter negative values as negative numbers. I: 9. 9}