The following data are from a completely randomized design. Treatment Treatment Treatment A C 32 46 32 30 45 35 30 46 34 26 48 35 32 50 39 Sample mean 30 47 35 Sample variance 6.00 4.00 6.50 a. At the a = 0.05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal? Compute the values below (to 1 decimal, if necessary). Sum of Squares, Treatment 583.3 X Sum of Squares, Error 66 Mean Squares, Treatment 371.6 X Mean Squares, Error 5.5 Calculate the value of the test statistic (to 2 decimals). 67.58 The p-value is between 0.01 and 0.025 v x What is your conclusion? Conclude that not all treatment means are equalPractice Sum of Squares, Treatment 583.3 X Sum of Squares, Error 66 Mean Squares, Treatment 371.6 X Mean Squares, Error 5.5 Calculate the value of the test statistic (to 2 decimals). 67.58 The p-value is |between 0.01 and 0.025 v X What is your conclusion? Conclude that not all treatment means are equal b. Calculate the value of Fisher's LSD (to 2 decimals). Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatments B and C. Use a = 0.05, Difference Absolute Value Conclusion CA - &B 17 Significant difference V X X CA- *0 - Select your answer - V 11 X - Select your answer - c. Use Fisher's LSD procedure to develop a 95% confidence interval estimate of the difference between the means of treatments A and B (to 2 decimals). Enter negative values as negative numbers