The following elementary, reversible organic liquid phase reaction $A+$BharrC is carried out in a

PFR$.$ An equimolar feed of A and $B$ enters at $27C,$ and the volumetric flow rate is $2d\frac{m^3}{s}$ and

$C_{A0}=0\mathrm{.}1$kmo$\frac{l}{m^3}.$ This reaction is carried out in a PFR with a heat exchanger of a size $10d{m}^3.$

Plot and then analyze $x$ and $x_{eq},T$ and $T_a,Q_r$ and $Q_g$ for the following cases while keeping track

of initial and final values.:

a$)$ Adiabatic operation

b$)$ Constant heat exchanger temperature $T_a$

c$)$ Co$-$Current heat exchanger $T_a$

d$)$ Countercurrent heat exchanger $T_a$

e$)$ Make a table of final $x,x_{eq},T,$ and $T_a$ for all of these systems. Write a conclusion based

on what you find.

Additional Information:

$H_A^o(273K)=-20$kca$\frac{l}{m}ol$

$H_B^o(273K)=-15$kca$\frac{l}{m}ol$

$H_C^o(273K)=-41$kca$\frac{l}{m}ol$

$C_{P,A}=C_{P,B}=15ca\frac{l}{\text{m}\text{o}\text{l}\text{K}}$

$C_{P,C}=30ca\frac{l}{mo{l}^2**(K)}$

$Ua=20ca\frac{l}{d{m}^3**s^{**}**(K)}$

$m_c=50\frac{g}{s}$

$T_{a0}=450K$

$C_{P,cl}=1ca\frac{l}{g**K}$

$k(300K)=0\mathrm{.}01d\frac{m^3}{mo{l}^{**}(s)}$ where $Ea=10,000ca\frac{l}{m}ol$

$K_C(450K)=10\frac{m^3}{k}mo{l}^2$

Please use polymath