The following figure shows an idealized picture of the seesaw, the one you used to determine the torques during the lab. This diagram was not adequate to describe this situation. As you saw in the lab, the seesaw went back to level when released in this configuration. 1. Determine the total torque around the pivot due to each 5-kg object, using the form t = F,r, if the seesaw is at an angle of 0 with respect to the ground. The following diagram better describes the situation seen in the simulation. F D r. F Note that the part ofri that is perpendicular to the force on the left is the green line, and the part of 12 that is perpendicular to the force on the right is the blue line. The length of the green line is Leos 0 + Dsin 0 and the length of the red line is Lcos 0- Dsin 0. 2. Using the form 1 = Fr,, determine the torque around point P due to each of the 5-kg objects that are a distance 2 meters from the center of the seesaw board. Using the counterclockwise direction as the positive direction, find the sum of the torques. What is the condition required for the seesaw to have zero torque?