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The following scores represent the final examination grades of the elementary statistics course: 23 60 79 32 57 74 52 70 82 36 80 77

The following scores represent the final examination grades of the elementary statistics course:

23 60 79 32 57 74 52 70 82 36 80 77 81 95

41 65 92 85 55 76 52 10 64 75 78 25 80 98

81 67 41 71 83 54 64 72 88 62 74 43 60 78

89 76 84 48 84 90 15 79 34 67 17 82 69 74

63 80 85 61

Provide a short yet informative interpretation of the stem- and - leaf plot.

1 | 0 5 7

2 | 3 5

3 | 2 4 6

4 | 1 1 3 8

5| 2 2 4 5 7

6| 0 0 1 2 3 4 4 5 7 7 9

7 | 0 1 2 4 4 4 5 6 6 7 8 8 9 9

8 | 0 0 0 1 1 2 2 3 4 4 5 5 8 9

9 | 0 2 5 8

LIKE THIS INTERPRETATION - FROM https://www.albert.io/blog/interpreting-stem-plots-what-to-know-for-ap-statistics/

image text in transcribed
Let's take the digits in the tens position as the stems and the digits in the ones position as the leaves. 6|578 7 | 0112334455579 8 I 1145599 9|02 How would you interpret this stem plot? It appears to show a normal nun/e. with no real outliers. The midterm exam scores range from 92-65. The median is 75, so 50% of the observations scored below 75 and 50% scored above 75. The mode. the most frequently occurring observation. is 75, like the median. The quartiles are 71.5 and 84.5. meaning that the middle 50% of the observations fall between these two scores. The interquartile range is 13. meaning that the middle 50% of the exam scores has a range by 13 points, suggesting that they are fairly close together. From this stem plot we can Characterize the distribution as being normally distributed. or a bell curve. That is. there do not seem to be any strange distribution in the data with extreme outliers. Visually, we can make a guess that there are no outliers. However. keep in mind that outliers must be calculated using the 1.5lQR rule

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