The formula for the braking distance of a car is:d =V/2g(f+ G)where:d is the braking distance (in feet)V is the initial velocity of the car

The formula for the braking distance of a car is:d =V²/2g(f+ G)where:d is the braking distance (in feet)V is the initial velocity of the car (in feet per second)G is the roadway grade (written in decimal form)f is the coefficient of friction between the tires and the roadwayg is the acceleration constant due to gravity (32.2 ft/sec²)a) If a car's speed was 47 miles per hour, what value would be used in this formula for V? Round to thetenths place.Recall 1 mile = 5280 feet.feet per secondb) If a car was going 86 feet per second when the driver applied the brakes, on a road with gradeG = 0.03 and a coefficient of friction of f = 0.8, what distance would it go before stopping? Round tothe tenths place.feet