1. (The function given below will be used for questions #1 - #5.)

Given : f(x)=x^2+6x+5

1. Find the x value of the vertex (turning point).

x = 3

x = -3

x = -2

None of the above

2. f(x)=x^2+6x+5

Using the same function as in #1, find the y value of the vertex.

None of the above

y = 32

y = 4

y = -4

3. Is this vertex you found above a minimum point or a maximum point?

Maximum point

Minimum point

4.What is the y-intercept of the function in #1?

(0, 5)

(5, 0)

None of the above

(0, 6)

5.What are the zeros of the parabola in #1? (that is, at what points does the graph cross thex-axis?)

{ (1, 0), (5, 0) }

{ (-1, 0), (-5, 0) }

None of the above

{ (0, -1), (0,-5) }

6.(Questions 6, 7, and 8 willuse the following 2 functions.)

Given : f(x)=x^2-4x-2

g(x)=x+7

Find :(f + g)(x)

7. Using the functions in #6 , find(f - g)(x)

8.Using the functions in #6 , find:

(f*g)(x)=

9. f(x)=1/x-2

g(x)=4x

Find (f*g)(x)=

10. using the functions in #9

find (g*f)(x)=

11.using the functions in #9

find (f*g)(3)=

14 Given the cubic function :

f(x)=(x-2)(x+2)(x-5)

What are the zeros of the cubic function?

{2, -2, 5}

{-2, 2, -5}

{-2, 0, 2}

None of the above

15. Given the cubic function from #14, what is the function's y-intercept?

None of the above

(0, 20)

(0, -20)

(0, -5)

16. Using the same function from #14, what is:

f(3)=

None of the above

f(3) = -10

f(3) = 10

f(3) = 4

17 (The following rational function will be used for questions 17, 18, and 19.)

Given :

f(x)=4x/x-2

What is thevertical asymptote?

x = -2

x = 0

x = 2

None of the above

18. Using the same function from #17, what is the function'shorizontalasymptote?

y = 0 (or the "x axis")

y = 4

y = -4

None of the above

19. Using the same function from #17, what is this function's y-intercept?

None of the above

(0, -2)

(0, 4)

(0, 0)

20. Given:

G(x)=1/2x+4

What is thehorizontal asymptote?

y=0 (the "x-axis")

y=4

y=

y=-2