The function given by y f(x) shows the value of $5000 invested at 4% interest compounded...

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The function given by y f(x) shows the value of $5000 invested at 4% interest compounded continuously, x years after the money was originally invested. (Round your answers to the nearest cent.) Value of $5000 with Continuous Compounding at 4% 24000-Value($) 20000- 14000- 12000- 3000-y= f(x) 4000- (5, 6107) (10, 7459) (25, 13,591) (20, 11,128) Part: 0/3 Part 1 of 3 Number of Years 10 20 The function given by y f(x) shows the value of $5000 invested at 4% interest compounded continuously, x years after the money was originally invested. (Round your answers to the nearest cent.) Value of $5000 with Continuous Compounding at 4% 24000-Value($) 20000- 14000- 12000- 3000-y= f(x) 4000- (5, 6107) (10, 7459) (25, 13,591) (20, 11,128) Part: 0/3 Part 1 of 3 Number of Years 10 20