The function h : 1R1 ) R defined by :1: 2 Mar) = 2:2 2:z:24 0 m=4or6 has a discontinuities at 4 and 6. At the discontinuity at 4 the left and right hand limits of h . If the function .71. can be turned into a function that is continuous at 4 by redfining the value of h( 4) only, enter that value below. If it can't be made continuous at 4 by redefining only h( 4) ),enter \"none" below. Enter your answer as an exact fraction, not as a decimal approximation. h(4)= :IE 2:754or6