The General Solution Of Dy/Dx = Xy^2 - X/Y Is In |Y^2 - 1| = Ln X + C Ln |Y^2 - 1| = Ce^X^2 Y^2 = Cx^2 - 1 Y^2 = Ce^X^2 + 1 None Of The Above. The Solution Of The Initial-Value Problem Y' + Y = 1/1 + E^X, Y(0) = Ln 6 Is Y = 2 Ln 3/1 + E^X Y = Ln(1 + E^X)/E^X + Ln 3/E^X Y = Ln(1 + E^X)/E^X - Ln 3/E^X Y = E^X/1 + E^X - Ln 3 None Of The Above.

 

1 of 3 3. The general solution of (a) Inly (b) Inly - 1 1 = = (c) y Cx-1 dy dx In x+C Cez (d) y = Ce+1 (e) None of the above. = xy-x y S 4. The solution of the initial-value problem y' + y = 2 In 3 (a) y = 1+ ex (b) y In(1+e*) In 3 + ex ex