The goal of this question is to guide you through the evaluation of the following integral, using an appropriate trigonometric substitution: Vx2 - 36 dx a > 0 a) First, select one of the following trig identities to be the backbone of your substitution: O tan?(0) + 1 = sec2(0) O sec2(0) - 1 = tan2(0) O 1 - sin2(0) = cos2 (0) Hint: Choose the trigonometric identity whose left side most resembles x- - 36. The right side of each identity is a perfect square which will ultimately help you to eliminate the radical and simplify the integral! b) Next, factor out 36 from the radical to obtain an expression of the form \\ x2 - 36 = 6 \\ A2 - 1. What is A? A = FORMATTING: The expression for A will depend on x. Since we cannot type the Greek letter 0 ("theta") in Mobius answers, we will use the variable Q in place of the traditional 0, for the remaining parts of this question. c) Choose a substitution for a so that the expression A - 1 (in terms of a) is exactly the left side of the trig identity from a). O x = 6sin-(Q) (where - ? FOFlMATTING: Your answer should depend on the variable Q Do not include the constant of integration in your answer; "+C \" is already written for you. i) Finally, rewrite your answer from h) in terms of the original variable (t. Hint: Parts d) and/or e) may be useful. :32 , 36 Final answer: f dz: : .B +C. m FORMATI'ING: Do not include the constant of integration in your answer; \"+C " is already written for you