The half-life of krypton-91 is 10 seconds. At time t = 0 a heavy canister contains 100 g of this radioactive gas. How much krypton;91 remains after 44 seconds? (Round your answer to three decimal places.) Hint: You'll need to use the function m(t) = mpe ", where m, is the initial mass of the radioactive substance, r is the relative decay rate, and mis the mass remaining at time t. Round your decay rate, r, to 6 decimal places. Then round the answer to the question to three decimal places