The heat capacity of methanol vapour is given by the following equation:

cp $=$ A $+$ BT$+$CT$2$

where A$=18\mathrm{.}38,$ B$=0\mathrm{.}1016,$ C$=2\mathrm{.}868\backslash$times $10-5($cp in J kg$-1$ K$-1,$ T in K$).$ Calculate the mean molar heat capacity of methanol between $25\backslash$deg C and $200\backslash$deg C in $($Btu lb$-1\backslash$deg F$-1).$