The heat of reaction for one mol of CaC2(s) CaC2 (s)+ 5H2O (l) = CaO (s) +2CO2 (g) + 5H2( g) is equal to 80.2 kJ.

You charge 110.9 grams of CaC2 (molar mass of CaC2= 64.1 g/mol) and liquid water into a rigid container at 25C, heat the container until the calcium carbide reacts completely, and cool the products back down to 25C, condensing essentially all the consumed water.

Calculate the net amount of heat in kJ that must be transferred to or from the reactor.

(hint: you need to calculate the internal energy first).