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The height (feet) of a ball launched in the air t seconds after it is launched is given by: f(t) = - 161 + 289t

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The height (feet) of a ball launched in the air t seconds after it is launched is given by: f(t) = - 161 + 289t + 19. The velocity of the ball at 15.7 seconds is fu/sec. If necessary, round to two decimal places. If there is more than one correct answer, separate them with commas

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