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The Henry's Law constant for oxygen in water at 299.0 K is equal to 43000 atm, with Po, = xo, Ho, - Mole Fraction of
The Henry's Law constant for oxygen in water at 299.0 K is equal to 43000 atm, with Po, = xo, Ho, - Mole Fraction of O2 in Water Calculate the mole fraction of O2 in water that is in equilibrium with air at 299.0 K and 1 atm. Xo = i x 10-5 Save for Later Attempts: 0 of 1 used Submit Answer Concentration of O2 in Water For water with small amounts of gas dissolved, the density and average molecular weight of the solution can be approximated by the density (use 1000 kg/m?) and molecular weight (18.02 g/mol) of pure water. Calculate the molar concentration of oxygen dissolved in water in equilibrium with air at 299.0 K (mol/m?). CO2 = i mol/m3 Save for Later Attempts: 0 of 1 used Submit Answer Concentration Ratio What is the ratio of the molar concentration (mol/m) of oxygen in the gas phase to that in the liquid phase at 299.0 K and 1 atm? Cg/0,- i Save for Later Attempts: 0 of 1 used Submit
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