The highest achievable resolving power of a microscope is limited only by the wavelength used; that is, the smallest item that can be distinguished has dimensions about equal to the wavelength. Suppose one wishes to "see" inside an atom. Assuming the atom to have a diameter of 600 pm, this means that one must be able to resolve a width of, say, 60 pm.,(a) If an electron microscope is used, what minimum electron energy is required? (b) If a light microscope is used, what minimum photon energy is required? (c) Which microscope seems more practical and why? (a) Number 0.0000000000000044 Units J/kg (b) Number 121.3 Units keVA particle of mass 3.19 x 10-27 kg has a potential energy of 7.12 x 10-15 J, independently of its position. If its energy is 11.0 x 10-15 J, what is its angular wave number? Number i 0.000000000000528 Units rad/m or m^ -1