The image shows what happens when you hold your arm straight. The deltoid l5\\ DCIIUILI muscle attaches at a distance of 17 cm from the shoulder and exerts a force on the upper arm that makes an angle of 15" with the arm. Suppose the weight of the arm is 20.0 N (that is, my = 20 N}. The weight of the arm is applied at the center of mass of the arm, which for simplicity, we can take to be the center of 1-} L}; the arm at a distance of 38 cm from the shoulder. 38 . cm (A) Take the bar below to represent the arm and the box is your torso. Draw the forces exerted on your arm. important: Notice how the force exerted by the deltoid pulls your arm into your body? This means that the body has to react and exert a force on the arm. Draw the x and y components of that force separately. You can figure out the direction of the x component from the other forces. For the y component, assume it's downwards. Torso 17 cm 38 cm (B) Pick a point of rotation and solve for the force the deltoid muscle must exert on the arm (call this FD for \"Force deltoid\"). How many times larger is this force than the weight ofthe arm? (Cl Calculate the x and y components of the force the torso exerts on the arm (call this F1- for "Force torso"). Then, calculate the magnitude of PT. How many times larger is this force than the weight of the arm? Important: Before you do any calculations, draw a free body diagram (FED) for the arm with the arm condensed to a single point. Include the x and y components of the force the torso exerts on your arm separately. (DJ Redo (A), except that now you are also holding a 30 lb (13.6 kg] dumbbell. You'll have all the same forces as in part (A) plus an additional one at the end of the bar that will be the weight of the dumbbell. Torso 17 cm 38 cm