The joint probability mass function of and is given by(1,1)=0.1 (2,1)=0.1 (3,1)=0.1 (1,2)=0.1 (2,2)=0.1 (3,2)=0.1 (1,3)=0.05 (2,3)=0.1 (3,3)=0.25

(a) Compute the conditional mass function of given =3:

(=1|=3)= (=2|=3)= (=3|=3)= (b) Are and independent? (c) Compute the following probabilities: P(X+Y>2)= P(XY=4)= P(X/Y>1)=