The language is R5RS can I have the solution in steps thank you.

(((lambda (x) (lambda (y) (+ x y))) 12) ((lambda (z) (* 3 z)) 3)) ((lambda (a b c) (list '(a b c) (list a b c) a 'b c)) 1 2 3) (((lambda (a) (lambda (b) '(lambda (c) '(a b c)))) 1) 2) (let ((a (lambda (x y) (list x y))) (b 2) (C 3)) (list (a b 'c) '(a b c)))