The logic of the following pseudocode is flawed.

create an empty stack.

balanced $=$ True

for each character in our input string:

if the character is an open bracket:

push it onto stack

elif the character is a closing bracket and stack is not enpty:

pop a character off of the stack

else:

balanced $=$ False

If balanced is still True:

print "balanced"

else:

print "unbalanced"

According to this pseudocode, which of the following unbalanced input strings will incorrectly print "balanced"?

Select one:

$(0(1))$

$(11)$

Clear my choice