The magnetic flux through the loop shown in the accompanying figure varies with time according to Im = Doe " sin(wt), where do = 5 x 10" T . m , a =1 s , and w =1207 rad/s. What are the direction and magnitude of the current through the 5-0 resistor at (a) t = 0; (b) t = 2.17 x 10 2 s, and (c) t = 3.00 s? 5.0 0 CO! . Hints a. Current Select an answer V with mA at t = 0. b. Current Select an answer V with mA at t = 2.17 x 10 - s. c. Current Select an answer with mA at t = 3.00 s