The mean age of De Anza College students in a previous term was 26.6 years old. An instructor thinks the mean age for online students is older than 26.6. She randomly surveys 60 online students and inds that the sample mean is 29.5 with a standard deviation of 2.1. Conduct a hypothesis test at the 5% level. Note: If you are using a Student's t-distribution for the problem, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.) + Part (a) [+ Part (b) + Part (c) Part (d) State the distribution to use for the test. (Enter your answer in the form z or tay where df is the degrees of freedom.) Part (e) What is the test statistic? (If using the z distribution round your answers to two decimal places, and if using the t distribution round your answers to three decimal places.) ---Select--- = Part (f) What is the p-value? Op-value 0.100 Explain what the p-value means for this problem. If Ho is true, then there is a chance equal to the p-value that the average age of online students is not 29.5 years or older. If Ho is false, then there is a chance equal to the p-value that the average age of online students is 29.5 years or older. If Ho is true, then there is a chance equal to the p-value that the average age of online students is 29.5 years or older. If Ho is false, then there is a chance equal to the p-value that the average age of online students is not 29.5 years or older.State the null hypothesis. O Ho: M 2 26.6 O Ho: M S 26.6 O Ho: M 26.6 + Part (b) + Part (c) + Part (d) + Part (e) + Part (f) + Part (9) + Part (h) Part (i) Construct a 95% confidence interval for the true mean. Sketch the graph of the situation. Label the point estimate and the lower and upper bounds of the confidence interval. (Round your answers to two decimal places.) 95% C.I