Question
The mean salary at a local industrial plant is $29,000$29,000 with a standard deviation of $4400$4400. The median salary is $26,900$26,900 and the 61 st
The mean salary at a local industrial plant is $29,000$29,000 with a standard deviation of $4400$4400. The median salary is $26,900$26,900 and the 61st percentile is $29,800$29,800.
Step 1 of 5:
Based on the given information, determine if the following statement is true or false.
Approximately 61%61% of the salaries are above $29,800$29,800.
Step 2 of 5
Based on the given information, determine if the following statement is true or false.
Joe's salary of $34,280$34,280 is 1.201.20 standard deviations above the mean.
Step 3 of 5:
Based on the given information, determine if the following statement is true or false.
The percentile rank of $27,100$27,100 is 5050.
Step 4
Based on the given information, determine if the following statement is true or false.
Approximately 11%11% of the salaries are between $26,900$26,900 and $29,800$29,800
Step 5
Based on the given information, determine if the following statement is true or false.
Approximately 11%11% of the salaries are between $26,900$26,900 and $29,800$29,800
If Tom's salary has a z-score of 0.60.6, how much does he earn (in dollars)?
Step 1-5 t/f
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