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The mean salary at a local industrial plant is $29,000$29,000 with a standard deviation of $4400$4400. The median salary is $26,900$26,900 and the 61 st

The mean salary at a local industrial plant is $29,000$29,000 with a standard deviation of $4400$4400. The median salary is $26,900$26,900 and the 61st percentile is $29,800$29,800.

Step 1 of 5:

Based on the given information, determine if the following statement is true or false.

Approximately 61%61% of the salaries are above $29,800$29,800.

Step 2 of 5

Based on the given information, determine if the following statement is true or false.

Joe's salary of $34,280$34,280 is 1.201.20 standard deviations above the mean.

Step 3 of 5:

Based on the given information, determine if the following statement is true or false.

The percentile rank of $27,100$27,100 is 5050.

Step 4

Based on the given information, determine if the following statement is true or false.

Approximately 11%11% of the salaries are between $26,900$26,900 and $29,800$29,800

Step 5

Based on the given information, determine if the following statement is true or false.

Approximately 11%11% of the salaries are between $26,900$26,900 and $29,800$29,800

If Tom's salary has a z-score of 0.60.6, how much does he earn (in dollars)?

Step 1-5 t/f

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