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The mean score on a test (out of 80) was found to be 64.2 and the standard deviation was determined to be 3.5 . Using
The mean score on a test (out of 80) was found to be 64.2 and the standard deviation was determined to be 3.5 .
Using the z-score chart,
a) Determine the probability that a student's score chosen at random is less than 72.
b) Determine the probability that a student's score chosen at random is greater than 72.
c) P(58< x <68) (score is between 58 and 68)
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