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The mean yearly precipitation in Toledo, Ohio is 99 inches. The population standard deviation is 19.08 inches and the yearly precipitation is normally distributed. What

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The mean yearly precipitation in Toledo, Ohio is 99 inches. The population standard deviation is 19.08 inches and the yearly precipitation is normally distributed. What is the probability that the percipitation of a random year will be less than 129 inches? Step 1: Determine the population mean and population standard deviation #: Step 2: Determine if we are trying to find the probability of x (individual) or T (sample mean). Then, explain in words what it represents based on the context of the problem. [7v]=[Selectananswer = V] Step 3: Determine your event and put it inside P. P([7v][7v) ) Step 4: Find your z-value and round the answer to six decimal places. &= Step 5: Now select your normal distribution curve with the correct fence(s) and shading and answer the questions below. - Im O Z 0 - Im Z O - Im O\f\fStep 6: For this problem, will we use invNorm() or normalcdf()? Please explain. Select an answerStep 6: For this problem, will we use invNorm() or normalcdf()? Please explain. Select an answer Select an answer invNorm() because we need find our area (probability) invNorm() because we need to find our z-value(s) Step normalcdf() because we need find our area (probability) en using your TI-84 calculator, the P normalcdf() because we need to find our z-value(s) percent rounded to two decinStep 7: Determine your event and put it inside P. Then using your TI-84 calculator, find the probability of your event. Write the answer as a percent rounded to two decimal places. P([2v][2v]| ) ~| % Step 8: Express the answer in words by completing the following sentence below. The chance that | Select an answer w | is |Select an answer v | is p

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