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The member below is composed of a tubular cylinder of stainless steel rigidly joined to a solid cylinder of carbon steel, one end of
The member below is composed of a tubular cylinder of stainless steel rigidly joined to a solid cylinder of carbon steel, one end of which is rigidly fixed to a wall. The composite member is subjected to the torques shown. Torsion testing measured the shear stress at the proportional limit to be 20 ksi for stainless steel and 24 ksi for carbon steel, and the shear strain at the proportional limit was 0.0020 for both materials. Calculate the angle in degrees that the free left end will twist with respect to the fixed right end of the composite cylinder. Take counterclockwise rotation looking towards the wall from the end of the tubular cylinder to be positive. Assume linear elastic behavior. Neglect any stress concentrations at the joints. Hint: The polar moment of inertia for a solid circular cross section is J = /2. 1/4" diameter hole 1000 in.-lb 0: 11 11 TI H 11 H 11 18" H stainless steel 4000 t in.-lb wall carbon steel 12" 2"
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To determine the angle in degrees that the free left end will twist with respect to the fixed right end of the composite cylinder we need to consider the torsional behavior of the stainless steel tubu...Get Instant Access to Expert-Tailored Solutions
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