The minimum distance reached between two electrons is of 3x10-10m. What is the electrons ve- locity when they are at a distance of 7x10-10m? The mass of the electron is 9.11 x 10-31kg and its charge is -1.6x10-19C. Ke, 1 + Ke,2 + Ue, 1 & 2 = Ke,1 + Ke,2 + Ue,1 & 2 Eel + Ee,2 = Eel + Ee,2 Kel = Ke,2 = 0 beacause at minimum distance the velocity is zero k QQ kee -+ -m v -m v2 + ri 2 2 k 02 k Q k 02 = m v Vf = ri m 1 = X 9x 109 Nm2 (-1.6 X 10-19C) 2 1 1 9.11 x 10-31kg C2 3 x 10-10m 7 x 10-10m Vf = 694,068.600 m