The National Retail Federation conducted a 2012 survey to determine the average amount of money spent on Valentine's Day. Suppose a sample of 2.500 people yielded a mean of $126.00 with a sample standard deviation of $75.00. Further, suppose that money spent is normally distributed. Determine the standard error of the mean. Answer 10 Points Tables Keypad Keyboard Shortcut O $1.50 O $1.60 O $1.70 O $1.80 According to the 2012 Harris Interactive Survey of American adults, the percentage of 25-29 year-olds with tattoos is 30% and the percentage of 50+ year-olds is 16%. Suppose that 120 of 400 25-29 year-olds had tattoos and that 65 of 410 50+ year-olds had tattoos, Determine the 90% confidence interval for the difference in population proportions use the difference of 25-29 year-olds and 50+ year-olds) Answer 10 Points m Tables Keypad Keyboard Shortcuts (0.09111.0.18889) (008125, 0.19825) 0 (0.09721.0,18279) 10.10191.0.17809) The budget director for a company is interested in comparing the daily travel expenses for the sales staff and the audit statt. The results of her study are presented below Staff Mean Daily Travel Expenses Sample Size Sample Standard Deviation of Daily Travel Expenses $20 Sales $160 40 Audit 130 15 45 Step 1 of 3: Construct the 90% confidence interval for the true difference (Sales Audity in the means Answer 10 Points Tables Keypad Keyboard Shortcuts 122.40.37.58) O 122.41, 37.59) (22.39. 37.57) (23.63.36.37) v Ne The budget director for a company is interested in comparing the daily travel expenses for the sales staff and the audit staff. The results of her study are presented below Sample Size Staff Mean Daily Travel Expenses Sample Standard Deviation of Daily Travel Expenses Sales $160 $20 40 Audit 130 15 45 Step 2 of 3: Construct the 95% confidence interval for the true difference (Sales - Audity in the means Answer 10 Points Tables Keypad Keyboard Shortcuts O (22.40, 37.58) O 122.39. 37.57