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The null and alternate hypotheses are: H0 : d 0 H1 : d > 0 The following sample information shows the number of defective units

The null and alternate hypotheses are:

H0 : d 0

H1 : d > 0

The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of 4 days last month.

Day 1 2 3 4 Day shift 11 12 13 19 Afternoon shift 9 10 14 15

At the .05 significance level, is there a difference in the mean number of citations given by the two shifts?

Required:

a. What is the p-value? NOTE: P-value calculators are available through online search. (Round your answer to 4 decimal places.)

b. What is your decision regarding the null hypothesis?

multiple choice Do not reject H0 Reject H0

c. What is the conclusion indicated by the analysis?

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