The null and the alternative hypotheses are as below: u1= mean number of Treatment 1 u2= mean number ofTreatment 2 u3= mean number of Treatment 3 HD1u1= u2= [13 Ha: At least two means are different [All means are not equal] Step 1: The value of the test statistic from the Excel prints out is F = 5.11??? Step 2: P-value m ethod Rejection Rule: Reject the null hypothesis whenever P value is less than the given level of significance 0.05 . Pvalue from the Excel printout is 0.024? F\"! D\" \"up...\" 0 F F We reject the hypothesis thatthe treatment means are equal since P-value of 0.024? is less than the given level of significance of 5% or 0.05 . Decision Explanation : We reject the hypothesis at the 5% level of significance that the treatment means are equal i.e. the mean of all the three treatments are significantly different. Step 2: Critical Value M ethod At the k1,nlk degrees of freedom, here 2, 12 at 5% level of significance level, the critical value of F = 3.89 . Rejection Rule: Reject HE| whenever the value of the test statistic greater than the critical value of 3.89