The number of accidents that a person has in a given year is a Poisson random variable with mean . However, suppose that the value of changes from person to person, being equal to 2 for 60 percent of the population and 4 for the other 40 percent. If a person is chosen at random, what is the probability that he will have (a) 0 accidents and (b) exactly 3 accidents in a certain year? What is the conditional probability that he will have 3 accidents in a given year, given that he had no accidents the preceding year? (a) The probability that he will have 0 accidents is (Type an integer or decimal rounded to three decimal places as needed.)