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The odds of winning the top prize in Mega Millions are always one in 302,575,350. The odds of winning the top prize in games like

The odds of winning the top prize in Mega Millions are always one in 302,575,350. The odds of winning the top prize in games like Pick 3 are also fixed. The odds of winning the top prize of $500 Pick 3 are one in 1,000. However, the odds are also influenced by the type of game chosen. For example, if you choose an Exact Order play for $1, your chances of winning the $500 top prize are one in 1,000. If you choose a 6-Way Combo play for $6, your chances of winning the $500 top prize are 1 in 166.7. The odds of winning on a single Combo Play ticket are the same as the odds of winning on six separate Exact Order tickets.

  • Display a probability table for this distribution
  • Convert the odds to probability. *Example is attached
  • What is your expected gain or loss from playing?
  • If you played 100 times how much would you expect to win or lose?
  • Is it binomial? Explain.
  • The following attachment is just an example!!!
image text in transcribed
Convert the odds to a probability To convert from odds to a probability, divide the odds by one plus the odds. So, to convert odds of 1/9 to a probability, divide 1/9 by 10/9 to obtain the probability of 0.10. Example: Taking the odds of 1:9 and knowing I'll win 1/10 times I have a probability of .10 of winning. This means I have a probability of .90 (the complement) of losing. Let's say if I spend a dollar, I could possibly win 2 dollars. If I lose, I lose the dollar. My distribution looks like this. X P(X) -$1 .9 (lose) $2 .1 (Win) Calculate expected value: E(x) = Sum (x* P(x)) E(x) = -l(.9) + 2(.l) = -.7 I expect to lose 70 cents ON AVERAGE each time I play. If I play 100 times, I'll lose .7(100) -- expected loss in one game times the number of times I play I expect to lose $70 dollars if I play 100 times. Why do I not expect to lose 100 dollars

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